Apply NTA CSIR UGC NET, JRF June Exam Online Form 2020 | Josforup

The Ministry of Human Resource Development (MHRD), Government of India (GOI), has establishedNationalTesting Agency (NTA) as an independent, autonomous and self-sustained premier organization under the Societies RegistrationAct, 1860, registered as a self-reliant and self-sustained premier testing organization.

Important Dates

  • Online Application Start : 16 March 2020
  • Registration Last Date : 15 April 2020
  • Fee Payment Last Date : 15 April 2020
  • Exam Date : 21 June 2020
  • Admit Card : June 2020
  • Answer Key Available : After Exam
  • Result Declared : Notified Soon

 Apply NTA CSIR UGC NET, JRF June Exam Online Form 2020 | Josforup

Apply Online (Registration) - Click Here

Candidates Login - Click Here

Download Notification - Click Here

Official Website - Click Here


Application Fee

  • General Candidates: Rs. 1000/-
  • OBC Candidates: Rs. 500/-
  • SC & ST Candidates : Rs. 250/-
  • PH Candidates: Rs. 250/-


      Age Limit as on 01/12/2020

      • For JRF : Maximum Age 28 Year.
      • For Lecturer / NET : No Age Limit

      Eligibility

      • Candidates have M.Sc Degree and Equivalent with 55% Marks For General / OBC Candidates For SC / ST Candidates 50% Marks.
      • Integrated Course and B.E / B.Tech / B.Pharma and MBBS Candidates Are also Available for CSIR NET 2019.

      Subject for Test

      • Chemical Science, Earth, Atmospheric, Ocean and Planetary Science.
      • Life Science, Mathematics Science, Physical Science.

      The pattern of Examination: 

      The Test will consist of three parts. All the parts will consist of objective type, multiple-choice questions. There will be no break between papers. The subject-wise scheme of examination is as per details below:

       Apply NTA CSIR UGC NET, JRF June Exam Online Form 2020 | Josforup

       Apply NTA CSIR UGC NET, JRF June Exam Online Form 2020 | Josforup

      Chemical Sciences: 

      The candidate is required to answer a maximum of 15, 35 and 25 questions from Part-A, Part-B and Part-C respectively. If more than required number of questions are answered, only first 15, 35 and 25 questions in Part A, Part B and Part C respectively will be taken up for evaluation. Below each question in Part A, Part B and Part C, four alternatives or responses are given. Only one of these alternatives is the "correct" option to the question. The candidate has to find, for each question, the correct or the best answer. 

      Earth Sciences: 

      The candidate is required to answer a maximum of 15, 35 and 25 questions from Part-A, Part-B and Part-C respectively. If more than required number of questions are answered, only first 15, 35 and 25 questions in Part A, Part B and Part C respectively will be taken up for evaluation. Below each question in Part A, Part B and Part C, four alternatives or responses are given. Only one of these alternatives is the "correct" option to the question. The candidate has to find, for each question, the correct or the best answer. 

      Life Sciences: 

      The candidate is required to answer a maximum of 15, 35 and 25 questions from Part-A, Part-B, and Part-C respectively. If more than required number of questions are answered, only the first 15, 35 and 25 questions in Part A, Part B, and Part C respectively will be taken up for evaluation. Below each question in Part A, Part B, and Part C, four alternatives or responses are given. Only one of these alternatives is the "correct" option to the question. The candidate has to find, for each question, the correct or the best answer. 

      Mathematical Sciences: 

      The candidate is required to answer a maximum of 15, 25 and 20 questions from Part-A, Part-B, and Part-C respectively. If more than required number of questions are answered, only first 15, 25 and 20 questions in Part A, Part B, and Part C respectively will be taken up for evaluation. Below each question in Part A, Part B, four alternatives or responses are given. Only one of these alternatives is the "correct" option to the question. The candidate has to find, for each question, the correct or the best answer. In Part C each question may have "ONE" or "MORE" correct options. Credit in a question shall be given only on identification of "ALL" the correct options in Part C.


      Physical Sciences: 

      The candidate is required to answer a maximum of 15, 20 and 20 questions from Part-A, Part-B, and Part-C respectively. If more than required number of questions are answered, only the first 15, 20 and 20 questions in Part A, Part B, and Part C respectively will be taken up for evaluation. Below each question in Part A, Part B, and Part C, four alternatives or responses are given. Only one of these alternatives is the "correct" option to the question. The candidate has to find, for each question, the correct or the best answer


      Mode of Examination: 

      The Examination shall be conducted as a Computer Based Test (CBT) only.


      2. Candidates can apply for CSIR-UGC NET December 2019 through “Online” mode only.

      3. Submission of Online Application Form may be done by accessing NTA website csirnet.nta.nic.in The Application Form in any other mode will not be accepted.

      4. Only one application is to be submitted by a candidate.

      5. Candidates must follow the instructions strictly as given in the Information Bulletin and on NTA website. Candidates not complying with the instructions shall be summarily disqualified.

      6. Candidates must ensure that E-mail Address and Mobile Number provided in the Online Application Form are their own as all information/ communication will be sent by NTA through e-mail on the registered e-mail address or SMS on registered Mobile Number only.

      7. Instructions for filling Online Application Form:


      Download Information Bulletin and Replica of Application Form. Read these carefully to ensure your eligibility.

      Follow the steps given below to Apply Online:

      Step-1: Apply for Online Registration using unique Email Id and Mobile No.


      Step-2: Fill in the Online Application Form and note down the system generated Application No.

      Step-3: Upload scanned images of Candidate’s Photograph (file size: 10 kb - 200 kb) and Candidate’s Signature (file size: 4kb - 30kb) in JPG/JPEG format.

      Step-4: Pay fee using SBI/Syndicate/HDFC/ICICI/Paytm Payment Gateway through Debit Card/Credit Card/Net Banking/UPI and keep proof of fee paid. In case the Confirmation Page is not generated after payment of fee then the transaction is canceled, and the amount will be refunded to the candidate’s account. However, the candidate has to make another transaction, in case the Confirmation Page is not generated.

      Download, save and print copies of Confirmation Page after successful remittance of fee and keep copies safely for future reference.

      All the 4 Steps can be done together or at separate times.

      8. Candidates are advised to visit the NTA website and check their e-mails regularly for the latest updates.

      9. The candidate shall appear at their own cost at the Examination Centre on Date and Shift indicated on their Admit Card issued by the NTA.

      10. Any request to change the Examination Centre, Date, Shift and NET Subject provided on the Admit Card shall not be considered under any circumstances.

      Note: 

      1. The final submission of the Online Application Form will remain incomplete if Step-3 and step-4 are not complete. Such forms will stand rejected and no correspondence on this account will be entertained.

      2. No request for refund of fee once remitted by the candidate will be entertained by NTA under any circumstances.

      3. The entire application process of CSIR-UGC NET December 2019 is online, including uploading of scanned images, Payment of Fees, and Printing of Confirmation Page. Therefore, candidates are not required to send/submit any document(s) including Confirmation Page to NTA through Post/ Fax/ by Hand/E-mail. 

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